Obtaining a controller for working with resources | HCL Digital Experience
To modify, create, or delete portal resources by using the Controller SPI, you first need to create a controller.
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You do this by using a JNDI based lookup for the correct "home"
interface, that is, the corresponding read-only interface.
Note: The provider
lookup for a controller home is possible from servlet level code and portlets.
The
following controllers are available via JNDI:
- ContentModelController
- To obtain a ContentModelController, perform a lookup for the string ContentModelControllerHome.CONTENT_MODEL_CONTROLLER_JNDI_NAME.
- PortletModelController
- To obtain a ContentModelController, perform a lookup for the string PortletModelControllerHome.PORTLET_MODEL_CONTROLLER_JNDI_NAME.
The LayoutModelController cannot be obtained via a JNDI lookup. You obtain it through its associated ContentModelController.
Example - Obtaining a content model
controller:
ContentModelController result = null;
final Context ctx = new InitialContext();
final ContentModelControllerHome home = (ContentModelControllerHome)
ctx.lookup(ContentModelControllerHome.CONTENT_MODEL_CONTROLLER_JNDI_NAME);
if (home != null) {
result = home.getContentModelControllerProvider().createContentModelController(aContentModel);
}
Note: To
obtain a
ContentModelController, you must pass an existing content
model to the createContentModelController method of the ContentModelControllerProvider. Example 2 - Obtaining a layout model controller for a specific page:
// locate the page for which you want to create a LayoutModelController
final Locator locator = cmController.getLocator();
final ContentPage page = (ContentPage) locator.findByUniqueName("MyPage");
// create a LayoutModelController
final LayoutModelController lmController = cmController.getLayoutModelController(page);