The ifx_int8copy() function

The ifx_int8copy() function copies one int8 structure to another.

Syntax

void ifx_int8copy(source, target)
   ifx_int8_t *source;
   ifx_int8_t *target;
source
A pointer to the int8 structure that contains the source int8 value to copy.
target
A pointer to the target int8 structure.

Return values

The ifx_int8copy() function does not return a status value. To determine the success of the copy operation, look at the contents of the int8 structure to which the target argument points.