getPort (XSPUrl - JavaScript™)
Gets the port number of the URL.
Defined in
XSPUrl (JavaScript)Syntax
getPort() : int| Return value | Description |
|---|---|
int |
The port number, or -1 if the port number is absent. |
Example
This example prints the port number of the URL for the current context.function p(stuff) {
print("<<<" + stuff + ">>>");
}
var url : XSPUrl;
var port : int;
try {
url = context.getUrl();
port = url.getPort();
if(port != -1)
p("getPort = " + port);
else
p("getPort = No port number");
} catch(e) {
p("Error = " + e);
}
Print output from the example might be as follows:
<<<getPort = 10038>>>